2x^(2/5)-x^(1/5)-1=0

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Solution for 2x^(2/5)-x^(1/5)-1=0 equation: 


x in (-oo:+oo)

2*x^(2/5)-x^(1/5)-1 = 0

t_1 = x^(1/5)

2*t_1^2-1*t_1^1-1 = 0

2*t_1^2-t_1-1 = 0

DELTA = (-1)^2-(-1*2*4)

DELTA = 9

DELTA > 0

t_1 = (9^(1/2)+1)/(2*2) or t_1 = (1-9^(1/2))/(2*2)

t_1 = 1 or t_1 = -1/2

t_1 = -1/2

x^(1/5)+1/2 = 0

1*x^(1/5) = -1/2 // : 1

x^(1/5) = -1/2

( -1/2 < 0 i 1/5 in (0:1) ) => x należy do O

t_1 = 1

x^(1/5)-1 = 0

1*x^(1/5) = 1 // : 1

x^(1/5) = 1

x^(1/5) = 1 // ^ 5

x = 1

x = 1

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